63 lines
1.6 KiB
Bash
63 lines
1.6 KiB
Bash
#!/bin/bash
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# 设置图片数量和输出文件名
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IMAGE_NUM_ALL=`ls /opt/websites/nav/assets/images/logos | wc -l`
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IMAGE_NUM_NEEDED=`cat /opt/websites/nav/index.html | grep -E '[0-9]{1,3}.jpg' | wc -l`
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if [[ $IMAGE_NUM_NEEDED -gt $IMAGE_NUM_ALL ]]; then
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alarm='Navigation:\nThere is NOT enough logos to use, please check ASAP.'
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bash /opt/scripts/alert/sendmsg.sh "$alarm"
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exit 233
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fi
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# 初始化数组
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declare -a arr=()
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# 随机选择图片名，不重复
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for ((i=0; i<$IMAGE_NUM_NEEDED; i++)); do
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while true; do
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# 随机生成图片名
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RAND=$((RANDOM%IMAGE_NUM_ALL))
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IMG_NAME=$RAND.jpg
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# 判断图片名是否已经被选择过
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chosen=0
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for num in "${arr[@]}"; do
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if [ "$num" == "$IMG_NAME" ]; then
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chosen=1
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break
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fi
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done
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# 如果图片名未被选择过，则将其添加到数组中
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if [ "$chosen" -eq 0 ]; then
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arr=(${arr[@]} $IMG_NAME)
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break
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fi
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done
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done
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# 需要修改的文件的路径和名称
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filename_origin="/opt/websites/nav/index.html"
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filename_copy="/opt/websites/nav/index_copy.html"
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cp $filename_origin $filename_copy
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# 循环处理所有符合指定模式的行
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let count=0
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lineno=1
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while read line; do
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# 获取文件名和路径
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oldname=$(echo $line | grep -Eo '[0-9]{1,3}.jpg')
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if [[ $oldname != '' ]]; then
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newname=${arr[$count]}
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# 替换文件名
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sed -i "${lineno}s/\/$oldname/\/$newname/" $filename_origin
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let count=count+1
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fi
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let lineno=lineno+1
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done < $filename_copy
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rm $filename_copy
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